Question

All the strings shown in figure are massless. Tension in the horizontal string is $30N$. find $W$.

Answer 1

Given,

Tension in horizontal cable,

$T_2\sin {45}^o=T_1$

$T_2=T_1\sqrt{2}=30\sqrt{2}\dots \dots \dots \left(1\right)$

Net force in y-direction is zero

$W=T_2\cos {45}^o=30\sqrt{2}\cos {45}^o=30N$

Hence, weight is $30N$