Question

All the vertices of a square lie on a circle. Find the area of square if the area of circle is $1256c{m}^2$.

Answer 1

$a^2=r^2+r^2\therefore a^2=2r^{2}Areaofcircle=\pi r^{2}1256=\left(\frac{22}{7}\right)\times r^2\left(\frac{1256\times 7}{22}\right)=\left(\frac{a^2}{2}\right)\therefore a^2=\left(\frac{1256\times 7\times 2}{22}\right)=800squnit\left(approx\right)$