${A l O}_{2}^{-}$ ion in aqueous solution exists as:

{[A l {(O H)}_{6}]}^{2 -}

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{[A l {(O H)}_{4} (H_{2} O)]}^{-}

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{[A l {(O H)}_{4} {(H_{2} O)}_{2}]}^{-}

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{[A l {(O H)}_{6}]}^{-}

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Solution

The correct option is C ${[A l {(O H)}_{4} {(H_{2} O)}_{2}]}^{-}$
Aluminate ion is isolated as $(A l O_{2})^{-}$ . But in the aqueous solution, this ion is surrounded by four water molecules. two water molecules react with the oxygen atom to produce 4 $O H^{-}$ ions.

So the formula of the overall complex will be $[A l (O H)_{4} (H_{2} O)_{2}]^{-}$ .

So the correct option is C.

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AlO−2 ion in aqueous solution exists as:

${A l O}_{2}^{-}$ ion in aqueous solution exists as: