You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

P-T Relationship

Along the lin...

Question

Along the line-1, mass of gas is $m_{1}$ and pressure is $P_{1}$ . Along the line-2 mass of same gas is $m_{2}$ and pressure is $P_{2}$ . Choose the correct options.

m_{1}

may be less than

m_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

m_{2}

may be less than

m_{1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P_{1}

may be less than

P_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P_{2}

may be less than

P_{1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A $m_{1}$ may be less than $m_{2}$
B $m_{2}$ may be less than $m_{1}$
C $P_{1}$ may be less than $P_{2}$
D $P_{2}$ may be less than $P_{1}$
From the ideal gas equation $P V = n R T$ ,

$\frac{V}{T} = \frac{m R}{M P}$

From the slopes of two curves,

$\frac{m_{1}}{P_{1}} > \frac{m_{2}}{P_{2}}$

Since only the ratio needs to satisfy the equality, both m and P can be changed in the same ratio to satisfy all the four options.

Hence answers are options A, B C and D.

Suggest Corrections

Similar questions

Q. Consider the following cell

P t | H_{2} (P_{1} a t m) | H^{+} (M_{1}) | | H^{+} (M_{2}) | H_{2} (P_{2} a t m) | P t

where

P_{1}

and

P_{2}

are pressures.

M_{1}

and

M_{2}

are molarities .
What will be the emf of cell at

25^{\circ} C

P_{1} = P_{2}

and

M_{1}

is 50% higher than

M_{2}

?
Repeat the magnitude of emf by multiplying with 10000.
[Take :

\frac{2.303 R T}{F} = 0.06 and log 3 = 0.48, log 2 = 0.3]

The pressure of the confined air in the right leg is $P_{1}$ . If the atmospheric pressure is $P$ , then

Q. Consider the following cell

P t | H_{2} (P_{1} a t m) | H^{+} (M_{1}) | | H^{+} (M_{2}) | H_{2} (P_{2} a t m) | P t

where

P_{1}

and

P_{2}

are pressures.

M_{1}

and

M_{2}

are molarities .
What will be the emf of cell at

25^{\circ} C

P_{1} = P_{2}

and

M_{1}

is 50% higher than

M_{2}

?
Repeat the magnitude of emf by multiplying with 10000.
[Take :

\frac{2.303 R T}{F} = 0.06 and log 3 = 0.48, log 2 = 0.3]

Two bodies of masses $m_{1}$ and $m_{2}$ have equal kinetic energies. If $p_{1}$ and $p_{2}$ are their respective momentum, then ratio $p_{1} : p_{2}$ is equal to

Q. Two chamber containing

m_{1}

and

m_{2}

grams of a gas at pressure

P_{1}

and

P_{2}

respectively are put in communication with each other, temperature remaining constant. The common pressure reached will be.

Join BYJU'S Learning Program

Along the line-1, mass of gas is m1 and pressure is P1. Along the line-2 mass of same gas is m2 and pressure is P2. Choose the correct options.

Along the line-1, mass of gas is $m_{1}$ and pressure is $P_{1}$ . Along the line-2 mass of same gas is $m_{2}$ and pressure is $P_{2}$ . Choose the correct options.