Question

$\alpha =0.99$ for a CE transistor amplified circuit. The input resistance is equal to $1$K $\Omega$ and load resistance is equal to $10$ K $\Omega$. The voltage gain of the circuit is _________.

• A. $99$
• B. $990$
• C. $9900$
• D. $99000$

Answer 1

Answer: (B)

$990$

Voltage gain =$\beta \times Resistancegain$

$\beta =\frac{\alpha }{1-\alpha }=\frac{0.99}{1-0.99}=99$

$Resistancegain=\frac{10\times {10}^3}{{10}^3}=10$

$\Rightarrow voltagegain=99\times 10=990$