- - - are the zeroes of cubic polynomial Px - ax3 - bx2 - cx - d- a - 0 then product of their zeroes - - - - - - -

The correct option is C da α, β and γ are zeros of P(x) Then, #160; α·β·γ = The constant termThe coefficient of x^3 = da Henc ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Relationship Between Zeroes and Coefficients of a Cubic Polynomial

α, β γ ar...

Question

$α, β$ & $γ$ are the zeroes of cubic polynomial $P (x) = a x^{3} + b x^{2} + c x + d, (a \neq 0)$ then product of their zeroes $[α . β . γ] =$ .................

\frac{- b}{a}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{c}{a}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{a}{b}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{- d}{a}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

α, β, γ

a x^{3} + b x^{2} + c x + d = 0

α + β + γ = \frac{- b}{a}

α, β, γ

P (x) = a x^{3} + b x^{2} + c x + d (a \neq 0)

\frac{1}{α} + \frac{1}{β} + \frac{1}{γ} =

α, β, γ

a x^{3} + b x^{2} + c x + d

α, β, γ

x^{3} - 2 x^{2} + q x - r

α + β = 0

2 q = r

α, β, γ

a x^{3} + b x^{2} + c x + d

α + β + γ = - \frac{b}{a}, α β + β γ + γ α = \frac{c}{a}, α β, γ = - \frac{d}{a}

α, β, γ

a x^{3} + b x^{2} + c x + d

= \frac{c}{a}

Join BYJU'S Learning Program