Question

$\alpha$- Particle of 6 MeV energy is scattered back from a silver foil. Calculate the maximum volume where the entire charge of atom is supported to be accumulated.

Answer 1

We know

$E=\frac{1}{4\pi \epsilon }\frac{\left(Ze\right)\left(2e\right)}{r}$

$r=\frac{9\times {10}^9\times 47\times 2\times (1.6\times {10}^{-19}{)}^2}{6\times {10}^6\times 1.6\times {10}^{-19}}$

$=2.25\times {10}^{14}m$

$V=\frac{4}{3}\pi r^3$

$=\frac{4}{3}\times \frac{22}{7}\times (2.25\times {10}^{14})$

$=48\times {10}^{-42}{m}^3$