Question

Altitude DE and BF of parallelogram ABCD are $4cm$ and $8cm$ respectively. One side AD is $6cm$ long. Find the perimeter of parallelogram ABCD

Answer 1

$DE=4cm$

$BF=8cm$

$AD=6cm$

Area of parallelogram $=AD\times BF$

$=6\times 8=48cm$

Now,

Area of parallelogram $=AB\times DE$

$\therefore AB\times 4=48$

$\Rightarrow AB=\frac{48}{4}=12cm$

Therefore,

Perimeter of parallelogram $=2(AB+AD)$

$=2\times (12+6)$

$=2\times 18=36cm$