Altitude DE and BF of parallelogram ABCD are $4 c m$ and $8 c m$ respectively. One side AD is $6 c m$ long. Find the perimeter of parallelogram ABCD

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Solution

$D E = 4 c m$
$B F = 8 c m$
$A D = 6 c m$

Area of parallelogram $= A D \times B F$

$= 6 \times 8 = 48 c m$

Now,

Area of parallelogram $= A B \times D E$

$∴ A B \times 4 = 48$

$\Rightarrow A B = \frac{48}{4} = 12 c m$

Therefore,

Perimeter of parallelogram $= 2 (A B + A D)$

$= 2 \times (12 + 6)$

$= 2 \times 18 = 36 c m$

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Altitude DE and BF of parallelogram ABCD are 4cm and 8cm respectively. One side AD is 6cm long. Find the perimeter of parallelogram ABCD

DE=4cmBF=8cmAD=6cmArea of parallelogram =AD×BF=6×8=48cmNow,Area of parallelogram =AB×DE∴AB×4=48⇒AB=484=12cmTherefore,Perimeter of parallelogram =2(AB+AD)=2×(12+6)=2×18=36cm

Altitude DE and BF of parallelogram ABCD are $4 c m$ and $8 c m$ respectively. One side AD is $6 c m$ long. Find the perimeter of parallelogram ABCD