Altitude of an equilateral triangle of side $2 a$ is

2 \sqrt{3} a

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\sqrt{3} a

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\frac{\sqrt{3}}{2} a

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\frac{a}{\sqrt{3}}

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Solution

The correct option is B $\sqrt{3} a$
$A n e q u i l a t e r a l t r i a n g l e w i t h s i d e 2 a A l t i t u d e = \frac{\sqrt{3} a}{2} A l t i t u d e = \frac{\sqrt{3}}{2} (2 a) = \sqrt{3} a H e n c e o p t i o n (B) i s t h e r i g h t a n s w e r$

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Similar questions

If ABC is an equilateral triangle of side a, prove that its altitude $= \frac{\sqrt{3}}{2} a$ [3 MARKS]

If ABC is an equilateral triangle of side a, prove that its altitude = $\frac{\sqrt{3}}{2}$ a

a

\frac{\sqrt{3} a}{2}

(2 a, 4 a), (2 a, 6 a)

(2 a + \sqrt{3} a, 5 a)

2 a

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