Aluminium chloride exists as a dimer, $A l_{2} C l_{6}$ in a solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives:

A l^{3 +} + 3 C l^{-}

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[A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}

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[A l (O H)_{6}]^{3 -} + 3 H C l

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A l_{2} O_{3} + 6 H C l

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Solution

The correct option is B $[A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}$
The aluminium chloride reacts with the water rather than just dissolving in it. In the first instance, hexaaquaaluminium ions are formed together with chloride ions.
$A l_{2} C l_{6} + H_{2} O \to [A 1 (H_{2} O)_{6}]^{3 +} + 3 C 1^{-}$
Hence option B is correct.

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Aluminium chloride exists as a dimer, Al2Cl6 in a solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives:

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Aluminium chloride exists as a dimer, $A l_{2} C l_{6}$ in a solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives: