Aluminium chloride exists as dimer, $A l_{2} C l_{6}$ in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives:

[A l (O H)_{6}]^{3 -} + 3 H C l

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A l_{2} O_{3} + 6 H C l

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A l^{3 +} + 3 C l^{-}

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[A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}

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Solution

The correct option is C $[A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}$
When ${A l}_{2} {C l}_{6}$ is dissolved in water, it is ionized to form ${[A l {(H_{2} O)}_{6}]}^{3 +}$ and ${C l}^{(-)}$ due to large hydration energy of ${A l}^{3 +}$ .
${A l}_{2} {C l}_{6} + 12 H_{2} O ⇌ 2 {[A l {(H_{2} O)}_{6}]}^{3 +} + {6 C l}^{(-)}$

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