Aluminium chloride exists as dimer, $A l_{2} C l_{6}$ in solid state as well as in solution of non-polar solvent such as benzene. When dissolved in water it gives:

Al₂O₃ + 6HCl

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[Al(H₂O)₆]³⁺ + 3Cl^–

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[Al(OH)₆]³^– + 3HCl

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Al³⁺ + 3Cl^–

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
[Al(H₂O)₆]³⁺ + 3Cl^–

Solution: AlCl₃ is hydrated in water after dissociation into ions as it behaves as an ionic compound. The interaction can be shown as:

$A l C l_{3} + 6 H_{2} O \to [A l (H_{2} O)_{6}] 3 + + 3 C l^{-}$

Suggest Corrections

Similar questions

Q. Aluminium chloride exists as dimer,

A l_{2} C l_{6}

in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives:

Aluminium chloride exists as a dimer ( $A l_{2} C l_{6}$ ) in solid state as well as in solution of non-polar solvents such as $C_{6} H_{6}$ . When dissolved in water it gives:

Q. Aluminimum chloride exists as dimer,

A l_{2} C l_{6}

, in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives :

Q. Aluminum chloride exists as a dimer

A l_{2} C l_{6}

solid state as well as in solution of non-polar solvents such as

C_{5} H_{5}

. When dissolved in water, it gives:

Q. Aluminum chloride exists as a dimer

A l_{2} C l_{6}

in solid state as well as in solution of non-polar solvents such as

C_{6} H_{6}

. When dissolved in acidified aqueous solution, it gives:

Join BYJU'S Learning Program

Aluminium chloride exists as dimer, Al2Cl6 in solid state as well as in solution of non-polar solvent such as benzene. When dissolved in water it gives:

The correct option is B [Al(H2O)6]3+ + 3Cl– Solution: AlCl3 is hydrated in water after dissociation into ions as it behaves as an ionic compound. The interaction can be shown as: AlCl3+6H2O→[Al(H2O)6]3++3Cl−

Aluminium chloride exists as dimer, $A l_{2} C l_{6}$ in solid state as well as in solution of non-polar solvent such as benzene. When dissolved in water it gives:

The correct option is B
[Al(H₂O)₆]³⁺ + 3Cl^–

Solution: AlCl₃ is hydrated in water after dissociation into ions as it behaves as an ionic compound. The interaction can be shown as:

$A l C l_{3} + 6 H_{2} O \to [A l (H_{2} O)_{6}] 3 + + 3 C l^{-}$