Aluminium chloride exists as dimer, $A l_{2} C l_{6}$ , in solid state as well as in solution of non-polar solvents such as $C_{6} H_{6}$ .

When dissolved in water it gives :

A l_{2} O_{3} + 6 H C l

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[A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}

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[A l (O H)_{6}]^{3 +} + 6 C l^{-}

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A l^{3 +} + 3 C l^{-}

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Solution

The correct option is C $[A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}$
Reaction:

$A l C l_{3}$ is covalent but in water it becomes ionic due to large hydration energy oh $A l^{3 +}$ .

$A l C l_{3} + 6 H_{2} O \to [A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}$ .

Hence,option B is correct.

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Similar questions

Aluminium chloride exists as dimer, $A l_{2} C l_{6}$ in solid state as well as in solution of non-polar solvent such as benzene. When dissolved in water it gives:

Q. Aluminum chloride exists as a dimer

A l_{2} C l_{6}

in solid state as well as in solution of non-polar solvents such as

C_{6} H_{6}

. When dissolved in acidified aqueous solution, it gives:

Q. Aluminimum chloride exists as dimer,

A l_{2} C l_{6}

, in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives :

Q. Aluminum chloride exists as a dimer

A l_{2} C l_{6}

solid state as well as in solution of non-polar solvents such as

C_{5} H_{5}

. When dissolved in water, it gives:

Q. Aluminium chloride exists as dime ,

A l_{2} C l_{6}

in solid state as well as in solution of non-polar solvents like benzene.When dissolved in water, it gives :

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Aluminium chloride exists as dimer, Al2Cl6, in solid state as well as in solution of non-polar solvents such as C6H6. When dissolved in water it gives :

The correct option is C [Al(H2O)6]3++3Cl−Reaction:AlCl3 is covalent but in water it becomes ionic due to large hydration energy oh Al3+.AlCl3+6H2O→[Al(H2O)6]3++3Cl−.Hence,option B is correct.

Aluminium chloride exists as dimer, $A l_{2} C l_{6}$ , in solid state as well as in solution of non-polar solvents such as $C_{6} H_{6}$ .

When dissolved in water it gives :

The correct option is C $[A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}$
Reaction:

$A l C l_{3}$ is covalent but in water it becomes ionic due to large hydration energy oh $A l^{3 +}$ .

$A l C l_{3} + 6 H_{2} O \to [A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}$ .

Hence,option B is correct.