Aluminium displaces hydrogen from dilute HCL whereas silver doesnot.The emf of a cell prepared by combining AL/AL*3+ is 2.46 V.The reduction potential of silver electrode is +0.80V.the reduction potential of alluminium electrode is
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Solution
-1.66 since aluminium displaces H+ from HCl and Ag doesn`t.... Hence Al is a reducing agent then, E•cell =E•cathode-E•anode. where cathode is silver metal , and anode is aluminium, because reducing agent(Al) is always can be anode in galvanic cell Then , 2.46=0.8-x x=0.8-2.46=-1.66