Aluminium is extracted from alumina $(A l_{2} O_{3})$ by electrolysis of a molten mixture of:

A l_{2} O_{3} + H F + N a A l F_{4}

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A l_{2} O_{3} + C a F_{2} + N a A l F_{4}

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A l_{2} O_{3} + N a_{3} A l F_{6} + C a F_{2}

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A l_{2} O_{3} + K F + N a_{2} A l F_{6}

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Solution

The correct option is C $A l_{2} O_{3} + N a_{3} A l F_{6} + C a F_{2}$
The electrolysis of pure alumina faces some difficulties. Pure alumina is a bad conductor of electricity.

The fusion temperature of pure alumina is about 2000 $^{\circ}$ C and at this temperature when electrolysis is carried out on the fused mass, the metal formed vaporizes, as the boiling point of aluminum is 1800 $^{\circ}$ C.

These difficulties are overcome by using a mixture containing alumina $(A l_{2} O_{3})$ , cryolite $(N a_{3} A l F_{6})$ , and fluorspar $(C a F_{2})$ .

Therefore, the correct option is $C$

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