Question

Aluminium reacts with chlorine gas to form aluminium chloride via the following reaction:
$2Al+3C{l}_2\to 2AlC{l}_3$
How many grams of aluminium chloride could be produced from 34 g of aluminium and 39 g of chlorine gas?

• A. 90.53 g
• B. 48.86 g
• C. 75.23 g
• D. 24.36 g

Answer 1

The correct option is B 48.86 g

Moles of aluminium = $\frac{34}{27}=1.259$
Moles of chlorine gas $=\frac{39}{71}=0.549$
As per the reaction, $2Al+3C{l}_2\to 2AlC{l}_3$
3 moles of chlorine gas react with 2 moles of aluminium
0.549 moles of chlorine react with $\frac{2}{3}\times 0.549=0.366$ moles aluminium
So, chlorine gas is limiting reagent
3 moles of chlorine gas produce 2 moles of aluminium chloride.
0.549 moles will produce $\frac{2}{3}\times 0.549=0.366$ moles Mass of $AlC{l}_3=0.366\times 133.5$ = 48.86 g