Aluminium reduces manganese dioxide to manganese at high temperature. The amount of aluminium required to reduce one gram mole of manganese dioxide is

1/2 gram mole

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 gram mole

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3/4 gram mole

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4/3 gram mole

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 4/3 gram mole
$4 A I + 3 M n O_{2} \to 3 M n + 2 A l_{2} O_{3}$
To reduce 3 moles of $M n O_{2}$ required moles of AI = 4
So, for one mole of $M n O_{2}$ required moles of AI will be = 4/3

Suggest Corrections

Similar questions

Chlorine is prepared in the laboratory by treating manganese dioxide (MnO₂) with aqueous hydrochloric acid according to the reaction

4HCl₍_aq₎ + MnO₂₍_s₎ → 2H₂O₍_l₎ + MnCl₂₍_aq₎ + Cl₂₍_g₎

How many grams of HCl react with 5.0 g of manganese dioxide?

H C l

Name a reducing agent that may be used to obtain manganese from manganese dioxide.

M O_{2})

M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} + 2 H_{2} O

5 g M n O_{2}

Join BYJU'S Learning Program