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Question

# Aluminum reacts with sulfuric acid to form aluminum sulfate and hydrogen. What is the volume of hydrogen gas in liters (L) produced at 300 K and 1.0 atm pressure, when 5.4 g of aluminum and 50.0 mL of 5.0 M sulfuric acid are combined for the reaction? (Use molar mass of aluminum as 27.0 g mol−1, R=0.082 atm L mol−1 K−1)

A
6.150
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B
6.1
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C
6.15
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Solution

## 2Al+3H2SO4→Al2(SO4)3+3H2Moles of Al taken=5.427=0.2Mole of H2SO4 taken=50×5/100=0.25As 0.2/2>0.25/3,H2SO4 is limiting reagentNow, moles of H2 formed=3/3×0.25=0.25 Therefore, Volume=0.25×0.082×300/1=24.6/4=6.15 L

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