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Question

AM is a median of a triangle ABC. Is AB + BC + CA > 2AM?

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Solution

AM is the median drawn from the vertex A to BC,

Applying the triangle inequality in the triangle ABM
AB + BM > AM —---(i)

Applying the triangle inequality in the triangle AMC
AC + MC > AM -----(ii)

Adding equations (i) and (ii) we get,
AB + BM + AC + MC > AM + AM
AB + AC + (BM + MC) > 2AM
AB + AC + BC > 2AM

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