Aman and Sindhu are playing on a seesaw. Aman weighs 450N and Sindhu weighs 300N. Aman is on one side sitting 3m away from the pivot. How far away must Sindhu sit (w.r.t pivot) to balance seesaw?
A
4m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4.5m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3.5m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B4.5m Moment of force is given by the product of the force and its distance from pivot.
Moment of force produced by Aman: M1=450N×3m=1350Nm
Let the distance between pivot and Sindhu be r. Moment of force produced by Sindhu: M2=300r
For seesaw to be in equilibrium, both the moments of force should be equal. 300r=1350 r=4.5m