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Question

Aman and Sindhu are playing on a seesaw. Aman weighs 450 N and Sindhu weighs 300 N. Aman is on one side sitting 3 m away from the pivot. How far away must Sindhu sit (w.r.t pivot) to balance seesaw?

A
4 m
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B
4.5 m
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C
2 m
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D
3.5 m
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Solution

The correct option is B 4.5 m
Moment of force is given by the product of the force and its distance from pivot.

Moment of force produced by Aman:
M1=450 N×3 m = 1350 N m

Let the distance between pivot and Sindhu be r.

Moment of force produced by Sindhu:
M2=300r

For
seesaw to be in equilibrium, both the moments of force should be equal.
300r=1350
r=4.5 m

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