Question

Aman tosses two unbiased coins. The probability that he gets at most one head is

• A.
  
  $\frac{2}{3}$
• B.
  
  $\frac{3}{4}$
• C.
  
  $\frac{1}{3}$
• D.
  
  $\frac{1}{2}$

Answer 1

The correct option is B


$\frac{3}{4}$
The outcomes when two unbiased coins are tossed are HH, HT, TH, TT.

$\therefore$ Total number of outcomes = 4

The outcomes favourable for getting at most one head are HT, TH, TT.

$\therefore$ Total number of favourable outcomes = 3

$\therefore$ Required probability

$=\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}=\frac{3}{4}$

Hence, the correct answer is option b.