Ambidentate ligand is

C_{2} O_{4}^{2 -}

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N O_{2}^{-}

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E D T A^{4 -}

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H_{2} O

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Solution

The correct option is B $N O_{2}^{-}$
$N O_{2}^{-}$ is a unidentate ligand having two different donor sites i.e., $N$ and $O$ . Therefore, it is an ambidentate ligand.

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Is H2O an ambidentate ligand or a unidentate ligand?

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