Amino group is ortho, para-directing for aromatic electrophilic substitution. On nitration of aniline good amount of m-nitroaniline is obtained. This is due to:

In nitration mixture, ortho-, para-activity of

N H_{2}

group is completely lost

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- N H_{2}

becomes

N H_{3}^{+}

, which is m-directing

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- N H_{2}

becomes

- N H^{+} S O_{4}^{-}

, which is m-directing

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- N H_{2}

becomes

- N H^{-} N O_{2}^{+}

, which is m-directing

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Solution

The correct option is B $- N H_{2}$ becomes $N H_{3}^{+}$ , which is m-directing
Nitration involves acidic medium, so protonation of aniline takes place forming anilinium ion (given) which being m-directing forms mainly m-nitroaniline.

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Amino group is ortho, para directing for aromatic electrophilic substitution. On nitration of aniline with concentrated acids, a good amount of meta nitro aniline is obtained. This is due to

Q. Assertion :

- {N H}_{2}

group of aniline is ortho, para directing in electrophilic substitutions. Reason:

- {N H}_{2}

group stabilises the arenium ion formed by the ortho, para attach of the electrophile

Give reasons of the following:

Although

- N H_{2}

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(b)

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yet aniline on nitration gives a significant amount of m - nitroaniline.

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If this is true enter 1 if false enter 0.

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Amino group is ortho, para-directing for aromatic electrophilic substitution. On nitration of aniline good amount of m-nitroaniline is obtained. This is due to:

The correct option is B −NH2 becomes NH+3, which is m-directingNitration involves acidic medium, so protonation of aniline takes place forming anilinium ion (given) which being m-directing forms mainly m-nitroaniline.

The correct option is B $- N H_{2}$ becomes $N H_{3}^{+}$ , which is m-directing
Nitration involves acidic medium, so protonation of aniline takes place forming anilinium ion (given) which being m-directing forms mainly m-nitroaniline.