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Question

Ammonia burns in oxygen and the combustion, in the presence of a catalyst, may be represented by:
2NH3+212O22NO+3H2O [H=1:N=14:O=16.]

What mass of steam is produced when 1.5 g of nitrogen monoxide is formed?

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Solution

Step 1: Balanced equation: 2NH3+212O22NO + 3 H2O

Step 2: Find the moles of NO by divide the mass by it's molar mass.

Moles of NO =1.5 gNO30 gmol of NO=0.05 moles of NO

Step 3: Find the moles of H2O by using the moles ratio from balanced equation

Moles of H2O = 0.05 moles NO×3 moles H2O2 moles of NO=0.075 moles of H2O

Step 4: Find the mass of H2O by multiply the molar mass

Mass of H2O = 0.075 moles H2O×18 g H2O1 mol of H2O=1.35 grams of H2O


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