Ammonia forms the complex $[C u (N H_{3})_{4}]^{2 +}$ with copper ions in alkaline solution but not in acidic solution. The reason for this is

In acidic solutions, protons coordinate with ammonia molecules

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In acidic solutions, hydration protects copper ions

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In alkaline solutions, insoluble

C u (O H)_{2}

is precipitated which is soluble in excess any alkali

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Copper hydroxide is an amphoteric substance

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Solution

The correct option is A In acidic solutions, protons coordinate with ammonia molecules
In acidic solution $N H_{3}$ lone pair get coordinated to $H^{+}$ and hence lp of 'N' has not been available to donate to copper thus making complex unstable in acidic solution.

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Similar questions

Ammonia forms the complex ion $[C u (N H_{3})_{4}]^{+ 2}$ with copper ions in alkaline solutions but not in acidic solutions. What is the reason for it?

Q. Statement-1 : Ammonia forms the complex

[C u (N H_{3})_{4}]^{2 +}

with copper ions in alkaline solution but not in acidic solution.
Statement-2 : In acidic solution protons are coordinated with ammonia molecules forming

N H_{4}^{+}

ions.

Q. Ammonia forms the complex ion

[C u (N H_{3})_{4}]^{2 +}

with copper ion in alkaline but not in acidic solution. What is the reason for it :

Q. Ammonia forms a complex ion

[C u (N H_{3})_{4}]^{2 +}

with copper ions in alkaline solutions but not in acidic solutions. What is the reason for it?

Q. Ammonia forms the complex ion

[C u (N H_{3})_{4}]^{2 +}

with copper ions in the alkaline solution because:

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Ammonia forms the complex [Cu(NH3)4]2+ with copper ions in alkaline solution but not in acidic solution. The reason for this is

The correct option is A In acidic solutions, protons coordinate with ammonia moleculesIn acidic solution NH3 lone pair get coordinated to H+ and hence lp of 'N' has not been available to donate to copper thus making complex unstable in acidic solution.

Ammonia forms the complex $[C u (N H_{3})_{4}]^{2 +}$ with copper ions in alkaline solution but not in acidic solution. The reason for this is

The correct option is A In acidic solutions, protons coordinate with ammonia molecules
In acidic solution $N H_{3}$ lone pair get coordinated to $H^{+}$ and hence lp of 'N' has not been available to donate to copper thus making complex unstable in acidic solution.