Ammonia gas dissolves in water to give $N H_{4} O H$ . In this reaction. water acts as :-

A n a c i d

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A b a s e

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A s a l t

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A c o n j u g a t e b a s e

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Solution

The correct option is A $A n a c i d$
$N H_{3}$ + $H_{2} O$ $\to$ $N H_{4}^{+}$ + $O H^{-}$
Water acts as a proton donor in this reaction. Since, a proton donor is an acid, water acts a Bronsted-Lowry acid.

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