Ammonia gas is passed into the water, yielding a solution of density $0.93 g / c m^{3}$ and containing $18.6$ % $N H_{3}$ by weight. The mass of ${N H}_{3}$ per cc of the solution is:

0.17 g / c m^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.34 g / c m^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.51 g / c m^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.68 g / c m^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $0.17 g / c m^{3}$
$18.6 %$ weight means $18.6 g N H_{3} i n 100 g o f$ solution

$V o l u m e o f s o l u t i o n = \frac{M a s s}{D e n s i t y} = \frac{100}{0.93 g / c m^{3}} \Rightarrow 107.52 c m^{3} .$

$M a s s o f N H_{3} p e r c c \Rightarrow \frac{18.6}{107.52} \Rightarrow 0.173 g / c m^{3}$

Hence, option $A$ is correct.

Suggest Corrections