Question

Ammonia is oxidized according to the following equation:
$4N{H}_3+5O_2\to 4NO+6H_{2}O$
​How many litres of nitric oxide are formed when 90 litres of oxygen reacts with ammonia? If 4 volume of ammonia reacts with 5 volume of oxygen to give 4 volume of nitric oxide.

• A. 48 litre.
• B. 56 litre.
• C. 18 litre.
• D. 72 litre.

Answer 1

The correct option is D

72 litre.

By gay lussac's law: 5 volume of oxygen reacts with 4 volume of ammonia to form 4 volume of nitric oxide.
Therefore 1 volume of oxygen reacts with $\frac{4}{5}$ volume of ammonia to form $\frac{4}{5}$ volume of nitric oxide. So, 90 litres of oxygen reacts with $90\times \frac{4}{5}$ ammonia to form $90\times \frac{4}{5}$ litres of nitric oxide i.e 72 litres of nitric oxide is formed.