Question

Ammonia reacts with excess chlorine to form:

• A. ${\mathrm{N}}_2\mathrm{and}{\mathrm{NH}}_4\mathrm{Cl}$
• B. ${\mathrm{NCl}}_3\mathrm{and}\mathrm{HCl}$
• C. ${\mathrm{N}}_2\mathrm{and}\mathrm{HCl}$
• D. ${\mathrm{NH}}_4\mathrm{Cl}\mathrm{and}{\mathrm{NCl}}_3$

Answer 1

The correct option is B

${\mathrm{NCl}}_3\mathrm{and}\mathrm{HCl}$

Explanation:

B. ${\mathrm{NCl}}_3\mathrm{and}\mathrm{HCl}$

The reaction of ammonia with chlorine:

• When Ammonia$\left({\mathrm{NH}}_3\right)$ reacts with excess chlorine$\left({\mathrm{Cl}}_2\right)$, it produces Nitrogen trichloride$\left({\mathrm{NCl}}_3\right)$ and Hydrogen chloride$\left(\mathrm{HCl}\right)$.
• The chemical reaction can be depicted as:
• ${\mathrm{NH}}_3\left(\mathrm{g}\right)+3{\mathrm{Cl}}_2\left(\mathrm{g}\right)\to {\mathrm{NCl}}_3\left(\mathrm{l}\right)+3\mathrm{HCl}\left(\mathrm{g}\right)$

Hence, the correct option is B i.e. ${\mathrm{NCl}}_3\mathrm{and}\mathrm{HCl}$.