Question

# Ammonia reacts with excess chlorine to form:

A

${\mathrm{N}}_{2}\mathrm{and}{\mathrm{NH}}_{4}\mathrm{Cl}$

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B

${\mathrm{NCl}}_{3}\mathrm{and}\mathrm{HCl}$

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C

${\mathrm{N}}_{2}\mathrm{and}\mathrm{HCl}$

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D

${\mathrm{NH}}_{4}\mathrm{Cl}\mathrm{and}{\mathrm{NCl}}_{3}$

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Solution

## The correct option is B ${\mathrm{NCl}}_{3}\mathrm{and}\mathrm{HCl}$Explanation:B. ${\mathrm{NCl}}_{3}\mathrm{and}\mathrm{HCl}$The reaction of ammonia with chlorine:When Ammonia$\left({\mathrm{NH}}_{3}\right)$ reacts with excess chlorine$\left({\mathrm{Cl}}_{2}\right)$, it produces Nitrogen trichloride$\left({\mathrm{NCl}}_{3}\right)$ and Hydrogen chloride$\left(\mathrm{HCl}\right)$.The chemical reaction can be depicted as: ${\mathrm{NH}}_{3}\left(\mathrm{g}\right)+3{\mathrm{Cl}}_{2}\left(\mathrm{g}\right)\to {\mathrm{NCl}}_{3}\left(\mathrm{l}\right)+3\mathrm{HCl}\left(\mathrm{g}\right)$Hence, the correct option is B i.e. ${\mathrm{NCl}}_{3}\mathrm{and}\mathrm{HCl}$.

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