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Question

Ammonia reacts with sulphuric acid to give the fertilizer ammonium sulphate. Calculate the volume of ammonia [at STP] used to form 59g of ammonium sulphate.
[N=14,H=1,S=32,O=16].

A
20.02 L
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B
24.33 L
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C
66.20 L
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D
34.12 L
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Solution

The correct option is A 20.02 L
2NH3+H2SO4(NH4)2SO4
Since, volume of one mole of ammonia at S.T.P. = 22.4 lit
So, volume of two moles of ammonia at S.T.P. = 22.4×2=44.8lit
Molecular weight of ammonium sulphate = 132
So, volume of Ammonia required to form 59 g ammonium sulphate
= 59×44.8132=20.02lit
So, correct answer is option A.

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