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Ammonia will ...

Question

Ammonia will not form complex ions with

A

{A g}^{+}

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B

{C d}^{2 +}

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C

{C u}^{2 +}

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D

{P b}^{2 +}

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Solution

The correct option is C ${A g}^{+}$
$P b^{2 +}$ ion do not from complex with ammonia. It precipitate in form of a White salt rather than forming. While $A g^{2 +}, C u^{2 +}, C d^{2 +}$ form soluble complexs with ammonia.

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Similar questions

State True or False.

C u^{2 +}

C d^{2 +}

ions react with KCN to form complex.

K_{4} [{F e (C N)}_{6}]

can be used to detect some ions out of

{C d}^{2 +}, {C u}^{2 +}, {Z n}^{2 +}, {F e}^{3 +}, {P b}^{2 +}

{B i}^{3 +}

. Excluded ions are :

Q. Ammonia will not form complex with:

Q. An aqueous solution contains

H g^{2 +}

H g_{2}^{2 +}

P b^{2 +}

C d^{2 +}

. Out of these, how many ions will produce white precipitate with

d i l u t e H C l

C u^{2 +}

C d^{2 +}

both are present, it is difficult to analyse. A scheme to analyse in a mixture is given below.
KCN forms complex with

C u^{2 +}

C d^{2 +}

C u^{2 +} + 2 C N^{-} ⟶ C u (C N)_{2}

C u (C N)_{2} ⟶ 2 C u C N ↓ + (C N)_{2}

C u C N + 3 K C N K_{3} C u (C N)_{4}] s t a b l e C d^{2 +} + K C N ⟶ K_{2} [C d (C N)_{4}] u n s t a b l e

H_{2} S

gas is passed, unstable complex of

C d^{2 +}

gives yellow ppt

[C d (C N)_{4}]^{2 -} ⇌ C d^{2 +} + 4 C N^{-}

C d^{2 +} + S^{2 -} ⟶ C d S y e l l o w ↓

If true enter 1, else enter 0.

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