Question

Amoeba undergoes binary fission. In this process, the parent amoeba splits into two daughter amoeba in stage $1.$ The process continues with the two daughter amoeba splitting into two each in stage $2$ to give rise to four amoeba in this stage. What will be the number of amoeba present after the completion of stage$n$?

Answer 1

In the stage $1$, the number of Amoeba = $1\times 2=2$

In the stage $2$, the number of Amoeba = $2\times 2=4$

In the stage $3$, the number of Amoeba = $3\times 2=6$

In the same way, in the stage $\mathrm{n}$, the number of Amoeba = $\text{n×2 = 2n}$

Hence, the number of amoeba present after the completion of stage $\mathrm{n}$ is $2n.$