Question

Among (A) - (D), the complexes that can display geometrical isomerism are:
$\left(A\right)\left[Pt\right(N{H}_3{)}_{3}Cl{]}^{+}$
$\left(B\right)\left[Pt\right(N{H}_3)C{l}_5{]}^{-}$
$\left(C\right)\left[Pt\right(N{H}_3{)}_{2}Cl\left(N{O}_2\right)]$
$\left(D\right)\left[Pt\right(N{H}_3{)}_{4}ClBr{]}^{2+}$

• A. $A$ and $B$
• B. $D$ and $A$
• C. $C$ and $D$
• D. $B$ and $C$

Answer 1

The correct option is A $A$ and $B$

The complexes of type $M{a}_{4}bc$ and $M{a}_2{b}_2$ can show geometrical isomerism provided $M{a}_2{b}_2$ is square planar. The compound given in $B$ is $M{a}_{4}bc$ type and compound given in $D$ is $M{a}_2{b}_2$ type. Also, in $D$, $Ni$ is surrounded with strong field ligands which will result in $ds{p}^2$ hybridisation and hence square planar geometry.