Question

Among $C{H}_4,N{H}_3$ and $H_{2}O$, acidity of $H_{2}O$ is maximum because :

• A. Oxygen contains two lone pairs of electrons.
• B. Bond angle on $H_{2}O$ is less than ${109}^{\circ }{28}^{\prime }$ due to $VSEPR$.
• C. Oxygen is more electronegative than $C$ or $N$.
• D. $H_{2}O$ is an associated liquid.

Answer 1

The correct option is C Oxygen is more electronegative than $C$ or $N$.

As oxygen is more electronegative so conjugate base in case of $H_{2}O$ is more stable and it is more basic than others.

The electronegativity increases along the period. Acidity of hydrides of corresponding elements also increase with increase in electronegativity of these elements.