Among five friends, who is the tallest ?
Statements:
1. D is taller than A and C.
2. B is shorter than E but taller than D.

I alone is sufficient while II alone is not sufficient

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II alone is sufficient while I alone is not sufficient

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Either I or II is sufficient

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Neither I nor II is sufficient

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Both I and II are sufficient

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Solution

The correct option is E Both I and II are sufficient
From I, we have: D > A, D > C.
From II, we have: E > B > D.
Combining the above two, we get :E > B > D > A > C or E > B > D >C > A.
Thus, E is the tallest.

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Similar questions

Among five friends---P, Q, R, S and T each of a different height, who is the second tallest? I. T is taller than S and Q. Q is shorter than S. II. R is taller than T. P is not the tallest.

Q. The given question consists of a set of statements. Find out whether the data provided in the statements are sufficient to answer the question and mark the option:

Among five friends - J, K, L, M and N each of a different height, who is the second tallest?
I. N is taller than M and K. K is shorter than M.
II. L is taller than N. J is not the tallest.

A, K, M and P are 4 friends. Who among them is the heaviest?

Statement I: P is heavier than M and K but lighter than A.

Statement II: M is lighter than P and A but heavier than K.

Q. Among friends M, N, O, P, Q and R, who is the second heaviest?

I. O is heavier than only two friends. P is heavier than O but lighter than N. R is the heaviest.
II. M is lighter than only two friends. N is heavier than O but lighter than R. P is heavier than only Q.

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Among five friends, who is the tallest ?Statements:1. D is taller than A and C.2. B is shorter than E but taller than D.

The correct option is E Both I and II are sufficientFrom I, we have: D > A, D > C.From II, we have: E > B > D.Combining the above two, we get :E > B > D > A > C or E > B > D >C > A.Thus, E is the tallest.

Among five friends, who is the tallest ?
Statements:
1. D is taller than A and C.
2. B is shorter than E but taller than D.

The correct option is E Both I and II are sufficient
From I, we have: D > A, D > C.
From II, we have: E > B > D.
Combining the above two, we get :E > B > D > A > C or E > B > D >C > A.
Thus, E is the tallest.