Among $K O_{2}, A l O_{2}^{-}, B a O_{2} a n d N O_{2}^{+}$ , unpaired electron is present in:

N O_{2}^{+} a n d B a O_{2}

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K O_{2} a n d A l O_{2}^{-}

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K O_{2}

only

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B a O_{2}

only

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Solution

The correct option is C $K O_{2}$ only
${N O}_{2}^{+} = 5 + 6 (2) - 1 = 16 ¯ e$
${A l O}_{2}^{-} = 3 + 6 (2) + 1 = 16 ¯ e$
$B a O_{2} = 2 + 6 (2) = 14 ¯ e$
${K O}_{2} = 1 + 6 (2) = 13 ¯ e$
Among all the four, only ${K O}_{2}$ has unpaired electrons in it.
If you notice the no. of electrons present in all the molecules, all have even number of electrons, except ${K O}_{2}$

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