The correct option is B Neither I nor II is sufficient
From I, we have: N > M, N > P, D > N. Thus, we have: D > N > M > P or D>N> P>M.
But, from II, M earns more than P i.e. D > N > M > P. Also, since P earns less than K and N earns less than only D, so we have: D>N>K>M>P or D>N>M> K > P.
Hence, either K or M earns more than only the least earner i.e. P.