Among $M g^{2 +}$ , $F e^{2 +}$ , $Z n^{2 +}$ and $C u^{2 +}$ which will get reduced first.

M g^{2 +}

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F e^{2 +}

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Z n^{2 +}

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C u^{2 +}

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Solution

The correct option is B $C u^{2 +}$
According to the electrochemical series we know that, metals at the top of the series have high value of negative electrode potential, which means they are good reducing agents. They give away electrons easily.
While, metals at the bottom of the series have positive value of electrode potential, which means they are good oxidizing agents. They accept electrons very easily.
$C u^{2 +}$ lies almost at the bottom of the electrochemical series. It has a positive electrode potential value. All the other mentioned metal ions lie towards the top of the series and have negative electrode potential value. Thus we can say that since $C u^{2 +}$ has positive electrode potential value it is the best oxidizing agent or the best at accepting electrons, among the four mentioned ions. Hence $C u^{2 +}$ will get reduced first, among the four mentioned ions.

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Similar questions

$E^{\circ}$ value of $M g^{2 +} | M g, Z n^{2 +} | Z n$ and $F e^{2 +} | F e$ are – 2.37 V, - 0.76 V and 0.44 V respectively. Which of the following is correct?

Q. Given ions are :

F e^{2 +}, N i^{2 +}, C a^{2 +}, K^{+}, M g^{2 +}, N a^{+}, C u^{2 +}, Z n^{2 +}

.
If all the given ions can form complexes then enter 1, else enter 0.

Q. Based on the following reactions, arrange the metals in increasing order of their reduction potentials.

Z n + C u^{2 +} \to Z n^{2 +} + C u

M g + Z n^{2 +} \to M g^{2 +} + Z n

C u + 2 A g^{+} \to C u^{2 +} + 2 A g

E^{o}

for

M g^{2 +} / M g = - 2.37 V, Z n^{2 +} / Z n = - 0.76 V

and

F e^{2 +} / F e = - 0.44 V

Which of the following statement is correct?

Q. SRP values of

M g^{2 +} | M g

F e^{2 +} | F e

and

Z n^{2 +} | Z n

are

- 2.37 V, - 0.44 V

and

- 0.76 V

respectively. The correct statement is:

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Among Mg2+, Fe2+, Zn2+ and Cu2+ which will get reduced first.

Among $M g^{2 +}$ , $F e^{2 +}$ , $Z n^{2 +}$ and $C u^{2 +}$ which will get reduced first.