Among $N a^{+}, N a, M g$ and $M g^{2 +}$ , the largest particle is:

M g^{2 +}

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M g

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N a

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N a^{+}

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Solution

The correct option is C $N a$
If we move from left to right along a period in the periodic table, size of the elements decrease because effective nuclear charge increases from left to right along a period.So size of Na is bigger than Mg.
Now size of any ion is smaller than it's parent element.So Na has larger size than $N a^{+}$ and Mg has larger size than $M g^{2 +}$ .
So decreasing order of size follows as Na>Mg> $N a^{+}$ > $M g^{2 +}$ .
For information size of each species are given bellow:
Na $= 154$ pm $N a^{+}$ = 116 pm, $M g = 130$ $M g^{2 +}$ $=$ 86 Pm.

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