Among $O, C, F, C l$ and $B r$ , the increasing order of atomic radii is:

F < O < C < C l < B r

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F < C < O < C l < B r

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F < C l < B r < O < C

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C < O < F < C l < B r

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Solution

The correct option is A $F < O < C < C l < B r$
Size increases on going down the group. Thus, size of $B r > C l > F$ . $F, C$ and $O$ are present in the same period.

Size decreases on going from left to right in a period.

Thus, the size of $C > O > F$ . Size of $C l > C$ as $C l$ is present in 3rd period and $C$ is present in 2nd period.

So, the correct order is : $B r > C l > C > O > F$ .

Hence, the correct option is $A$

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Similar questions

Q. Arrange in the increasing order of atomic radii of the following elements O, C, F, Cl, Br.

Q. The correct order of polarizability is

I^{-}, B r^{-}, C l^{-}, F^{-}

Which of the following is not correct?

$O r d e r o f b a s i c i t y O r d e r o f n u c l e o p h i l i c i t y (a) F^{-} > C l^{-} > B r^{-} B r_{-} > C l^{-} > F^{-} (b) H - O - O^{-} > O H^{-} H - O - O^{-} > O H^{-} (c) C H_{3} > N H_{2}^{-} > O H - C H_{3} > N H_{2}^{-} > O H^{-} (d) H_{2} O > H_{2} S H_{2} O < H_{2} S$

Among halogens, the correct order of amount of energy released in electron gain (electron gain enthalpy ) is
(a) F > Cl > Br > I (b) F < Cl < Br < I (c) F < Cl > Br > I (d) F < Cl < Br < I

The electronegativity order of O, F, Cl and Br is:

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Among O,C,F,Cl and Br, the increasing order of atomic radii is:

Among $O, C, F, C l$ and $B r$ , the increasing order of atomic radii is: