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Question

Among the different arrangements of 8 unit square crackers, which of the following arrangements will have the least perimeter?

A
1×8
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B
4×2
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Solution

The correct option is B 4×2
For 8 square crackers we can have two arrangements
i.1×8 or ii.4×2 as shown:


For the first case i.e. 8×1
Its perimeter can be calculated as 2×(8+1)=18 units.

Similarly for the second case i.e. 4×2
Its perimeter can be calculated as 2×(4+2)=12 units.

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