Question

Among the different arrangements of $8$ unit square crackers, which of the following arrangements will have the least perimeter?

• A. $1\times 8$
• B. $4\times 2$

Answer 1

The correct option is B $4\times 2$

For 8 square crackers we can have two arrangements
$i.1\times 8$ or$ii.4\times 2$ as shown:


For the first case i.e. $8\times 1$
Its perimeter can be calculated as $2\times (8+1)=18$ units.

Similarly for the second case i.e. $4\times 2$
Its perimeter can be calculated as $2\times (4+2)=12$ units.