Among the electrolytes $N a_{2} S O_{4}, C a C l_{2}, A l_{2} (S O_{4})_{3}$ and $N H_{4} C l$ , the most effective coagulating agent for $A s_{2} S_{3}$ sol is :

N a_{2} S O_{4}

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C a C l_{2}

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A l_{2} (S O_{4})_{3}

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N H_{4} C l

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Solution

The correct option is C $A l_{2} (S O_{4})_{3}$
Hardy- Schulze Law states that greater the valency of the active ion, greater is the power to cause coagulation. Active ion is responsible for coagulation.

In the case of negatively charged sols ( $A s_{2} S_{3}$ is a negative sol), the coagulation power is in order of $A l^{+ 3} > C a^{+ 2} > N a^{+}$ .

Hence, the most effective coagulating agent for $S b_{2} S_{3}$ is $A l_{2} (S O_{4})_{3}$ .

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Similar questions

Among the electrolytes $N a_{2} S O_{4}, C a C l_{2}, A l_{2} (S O_{4})_{3}$ and $N H_{4} C l$ , the most effective coagulating agent for $S b_{2} S_{3}$ sol is

Q. Among the electrolytes

N a_{2} S O_{4}

C a C l_{2}

A l_{2} (S O_{4})_{3}

, and

N H_{4} C l

, the most effective coagulating agent for

S b_{2} S_{3}

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Q. Among the electrolytes

N a_{2} S O_{4}, C a C l_{2}, A l_{2} (S O_{4})_{3}

and

N H_{4} C l,

the most effective coagulating agent for

S b_{2} S_{3}

solution is:

Q. Among the electrolytes,

N a_{2} S O_{4}, C a C l_{2}, A l_{2} (S O_{4})_{3}

and

N H_{4} C l

, the most effective coagulating agent for

S b_{2} S_{3}

solution is:

Q. Among the electrolytes given below

K_{2} S O_{4}, B a C l_{2}, A l_{2} (S O_{4})_{3}

and

N H_{4} C l

which will be the most effective coagulating agent for

S b_{2} S_{3}

sol?

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Among the electrolytes Na2SO4,CaCl2,Al2(SO4)3 and NH4Cl, the most effective coagulating agent for As2S3 sol is :

Among the electrolytes $N a_{2} S O_{4}, C a C l_{2}, A l_{2} (S O_{4})_{3}$ and $N H_{4} C l$ , the most effective coagulating agent for $A s_{2} S_{3}$ sol is :