Question

Among the elements with atomic numbers $9$, $12$, $16$, and $36$ which is highly electropositive?

• A. Element with atomic number $9$
• B. Element with atomic number $12$
• C. Element with atomic number $16$
• D. Element with atomic number $36$

Answer 1

The correct option is B Element with atomic number $12$

$z\left(9\right)=1s^{2}2s^{2}2p^5$

$z\left(12\right)=1s^{2}2s^{2}2p^{6}3s^2$

$z\left(36\right)=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^6$

Hence, the element with $z=12\left(Mg\right)$ is highly electropositive in nature. Since by using two value electrons, it will have the configuration of the noble gas Neon.

Hence, the correct option is $\text{B}$