Question

Among the first lines, Lyman, Balmer, Paschen and Brackett series in hydrogen atomic spectra, which has higher energy?

• A. Lyman
• B. Balmer
• C. Paschen
• D. Brackett

Answer 1

The correct option is A Lyman

Energy, $\Delta E=13.6(\frac{1}{n_1^2}-\frac{1}{n_2^2})eV$

For the first line of Lyman series:

$n_1=1,n_2=2$

$\Delta E=13.6(\frac{1}{1^2}-\frac{1}{2^2})eV=10.2eV$

and energy decreases as we move on to the next series.

Option A is correct.