Among the following complexes (K-P) :
$K_{3} [F e (C N_{6}] - K$ and $[C o (N H_{3})_{6}] C l_{3} - L$ ;
$N a_{3} [C o (o x a l a t e)_{3}] - M$ and $[N i (H_{2} O)_{6}] C l_{2} - N$ ;
$K_{2} [P t (C N)_{4}] - O$ and $[Z n (H_{2} O)_{6}] (N O_{3})_{2} - P$ ;
the diamagnetic complexes are:

K,L,M,N

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K,M,O,P

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L,M,O,P

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Solution

The correct option is D L,M,O,P
$K_{3} [F e (C N_{6}] - K$ = $3 d^{5}$ it is paramagnetic

$[C o (N H_{3})_{6}] C l_{3} - L$ = $3 d^{6}$ is diamagnetic

$N a_{3} [C o (o x a l a t e)_{3}] - M$ = $3 d^{6}$ is diamagnetic

$[N i (H_{2} O)_{6}] C l_{2} - N$ = $3 d^{8}$ is paramagnetic

$K_{2} [P t (C N)_{4}] - O$ = $d^{3}$ it is diamagnetic

and $[Z n (H_{2} O)_{6}] (N O_{3})_{2} - P$ ;= $d^{6}$ it is diamagnetic

Suggest Corrections

Similar questions

(K) : K_{3} [F e (C N)_{6}]

(L) : [C o (N H_{3})_{6}] C l_{3}

(M) : N a_{3} [C o (o x a l a t e)_{3}]

(N) : [N i (H_{2} O)_{6}] C l_{2}

(O) : K_{2} [P t (C N)_{4}]

(P) : [Z n (H_{2} O)_{6}] (N O_{3})_{2}

(K - P) K_{3} [F e (C N)_{6} (K), [C o (N H_{3})_{6}] C l_{3} (L), N a_{3} [C o (o x a l a t e)_{3}] (M), [N i (H_{2} O)_{6}] C l_{2} (N), K_{2} [P t (C N)_{4}] (O) and [Z n (H_{2} O)_{6}] (N O_{3})_{2} (P)

K : K_{4} [M n (C N)_{6}], L : K_{3} [C o (N O_{2})_{6}], M : [C o (H_{2} O)_{6}] C l_{3}, N : [C r (C O)_{6}], O : [N i (e n)_{3}] (N O_{3})_{3}

P : [P t (N H_{3})_{2} C l_{2}]

In Figure, $P L ⊥ O A$ and $P M ⊥ O B$ such that $P L = P M$ . Is $Δ P L O ≅ Δ P M O$ ?
Give reasons in support of your answer.