Among the following compounds the least basic compound is:
$C_{3} H_{7} N H_{2}, N H_{3}, C H_{3} N H_{2}$ and $C_{6} H_{5} N H_{2}$

C_{3} H_{7} N H_{2}

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N H_{3}

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C H_{3} N H_{2}

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C_{6} H_{5} N H_{2}

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Solution

The correct option is D $C_{6} H_{5} N H_{2}$
$C_{6} H_{5} N H_{2}$ is least basic compound due to resonance by which the lone pair of nitrogen takes part in resonance. Due to unavailability of lone pair on $N$ , aniline become less basic. The lone pair of $N$ is delocalized into benzene ring through resonance.

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Similar questions

C H_{3} N H_{2}, (C H_{3})_{2} N H, N H_{3}, C_{6} H_{5} N H_{2}

Arrange the following in increasing order of their basic strength:

(i) C₂H₅NH₂, C₆H₅NH₂, NH₃, C₆H₅CH₂NH₂ and (C₂H₅)₂NH

(ii) C₂H₅NH₂, (C₂H₅)₂NH, (C₂H₅)₃N, C₆H₅NH₂

(iii) CH₃NH₂, (CH₃)₂NH, (CH₃)₃N, C₆H₅NH₂, C₆H₅CH₂NH₂.

C_{2} H_{5} N H_{2}, N H_{3}, C_{6} H_{5} N H_{2}

C_{6} H_{5} N H_{2} (I), (C_{6} H_{5})_{2} N H (I I), C H_{3} N H_{2}, N H_{3} (I V) (I I I)

C_{6} H_{5} N H_{2}

C_{2} H_{5} N H_{2}

N H_{3}

(C H_{3})_{2} N H

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