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Question

Among the following compounds the one that is paramagnetic is:


A

O22-

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B

O3

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C

N2O

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D

O2-

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Solution

The correct option is D

O2-


Explanation for correct option:

D. O2-

Paramagnetic compounds:

  • "Paramagnetic compounds/ ions are the ones that have at least one unpaired electron.
  • In O2-, the total number of valence electrons are 17.
  • The electronic configuration can be written as: σ1s2,σ1s2,σ2s2,σ2s2,σ2pz2,π2px2=π2py2π*2px2=π*2py1 .
  • As O2- has one unpaired electron. Thus it is paramagnetic in nature.

Explanation for incorrect options:

A. O22-

  • The total number of electrons present in O22are 18.
  • The electronic configuration can be written as: σ1s2,σ1s2,σ2s2,σ2s2,π2px2=π2py2,σ2pz2,π2px2=π2py2
  • Hence it is not paramagnetic as it does not have any unpaired electron.

B. O3

  • The total number of valence electrons is O3 are 24.
  • It is not paramagnetic in nature.

C. N2O

  • The total number of valence electrons in N2O is 18.
  • The electronic configuration can be written as: σ1s2,σ1s2,σ2s2,σ2s2,σ2pz2,π2px2=π2py2,π2px2=π2py2
  • Hence, it is diamagnetic in nature.

Therefore, the correct option is D i.e. O2-.


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