The correct option is
D HClO2 Option (a)
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/780430/original_unnamed_28229.png)
Here, Central atom (C) is having 3
σ bonds and zero lone pair. So steric number is
3+0=3. So Hybridisation is
sp2. Also it is having trigonal planar structure.
Option(b)
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/780440/original_unnamed_28129.png)
Here, Central atom (
Si) is having 4
σ bonds and zero lone pair. So steric number is
4+0=4. So Hybridisation is
sp3. It has regular tetrahedral geometry and is non-polar.
In Option (c) and (d)
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/782673/original_25_28229.png)
Here, Central atom (B) is having 3
σ bonds and zero lone pair. So steric number is
3+0=3. So Hybridisation is
sp2. Also it is having symmetrical trigonal planar structure so it is non-polar.
In
HClO2 Central atom (C) is having 2
σ bonds and two lone pair. So steric number is
2+2=4. So Hybridisation is
sp3. Since it is having unsymmetrical angular structure so it is polar.